1$0$3.141592654$13$2$.5$2$.5$1000$2$2$1.4$4$2$2.5$.1$3.5$.25$4$2$2$.75$4$1.5$1.4$83$100$10$4$4$1.5$2$.5$100$4$1000000$4$2$1000$6.283185307$.5$12.56637061$2$2$2$2$2$2$3.14159$100$100$.09$.14$.22$.312$12$.081$13$.072$14$.064$15$.057$16$.051$17$.045$18$.040$19$.036$20$.32$21$.0285$22$.0253$23$.0226$24$.0201$25$.0179$26$.0159$27$.0142$28$.0126$29$.0113$30$.01$31$.0089$32$.008$33$.0071$34$.0063$35$.0056$36$.005$37$.0045$38$.004$39$.0035$40$.0031$12$40$40$4$4$4$18$2$40$4$4$4$18$2$10$10$100$100$492$.05$2$492$30$.95$150$.97$149.9$.98$118$148$.1264$2$.1593$3$.2009$4$.2533$5$.3195$6$.4028$7$.5080$8$.6405$9$.8077$10$1.018$11$1.284$12$1.619$13$2.042$14$2.575$15$3.247$16$4.094$17$5.163$18$6.51$19$8.21$20$10.35$21$13.05$22$16.46$23$20.76$24$26.17$25$33$26$41.62$27$52.48$28$66.17$29$83.44$30$105.2$31$132.7$32$167.3$33$211$34$266$35$335$36$423$37$533$38$672.6$39$848.1$40$1069$3$1.6$4$4.4$1.8$1.4$5.68$12.8$5.1$4$.94$11$6.7$3.4$1000$1000$.1264$.1593$2$.2009$3$.2533$4$.3195$5$.4028$6$.5080$7$.6405$8$.8077$9$1.018$10$1.284$11$1.619$12$2.042$13$2.575$14$3.247$15$4.094$16$5.163$17$6.51$18$8.21$19$10.35$20$13.05$21$16.46$22$20.76$23$26.17$24$33$25$41.62$26$52.48$27$66.17$28$83.44$29$105.2$30$132.7$31$167.3$32$211$33$266$34$335$35$423$36$533$37$672.6$38$848.1$39$1069$40$1000$1000$3$5.5$5$24$8.7$3$8$11.7$9$18$*8���)          *** ELECTRICAL ENGENEERING & DESIGN ***�$4                 J. Schrabal, April 1979�$44File cleaned up of typos and put somewhat of a structure�$4in it: 8/25/82 by S. Kluger�$44€�.�To select one of the programs just type it's number�$4and hit 'RETURN' key. Enter all alphabetic answers in UPPER CASE!�$44Select from the following routines (0 to quit) :�$4     1. Ohm's law (DC)�$4     2. Zener stabilized DC supply�$4     3. DC power supply design�$4     4. Low pass 2-pole Butterworth filter�$4     5. Series resonant frequency circuit�$4     6. Passive band-pass filter�$4     7. Small coil design & inductance calculations�$4     8. Long wire antenna�$4     9. Dipole or half wave antenna�$4    10. Time constant calculation�$4    11. Resistance of wire�$4    12. Crystal (rec./tr.) frequency calculations�$44What routine do you wish to select�$4;€"'À.�À.�7‰6ÁÀ.�7•68Please answer with number fom 0 to 12�$46AÀ[€\96ì6‰6	L6Ì6o6Ã6ú6'q6),6+ë6-_65f4          *** OHM's LAW (DC) ***�$44 ENTER values for 2 (two) known�$4 ENTER 0 (zero) for unknown values to be calculated�$44Potential in volts �$4;€"'Current flow in amperes �$4;€"'À.�À.�7¿6vResistance in ohms�$4;€"'À.�À.�À.�7õ6À.�À.�À.�76ŒPower in watts �$4;€"'À.�À.�À.�7B6ŸÀ.�À.�À.�7\6¶À.�À.�À.�7v6É€ÀÀ6”€ÀÀ6”€ÀÀ€ÀÀ6Ý€ÀÀ€À.�À6Ý€ÀÀ€ÀÀ6Ý€ÀÀ.�€ÀÀ4Potential = �$À# volts�$4Current flow = �$À# amperes�$4Resistance = �$À# ohms�$4Power = �$À# watts�$44MORE CALCULATIONS? (YES/NO)�$4;€1'ÀYES�7†66‰6A4      *** ZENER STABILIZED CIRCUIT DESIGN ***�$44Voltage rating of zener diode�$4;€"'Wattage rating of zener diode�$4;€"'Maximum DC voltage of power supply�$4;€	"'€À	À.�À€ÀÀ.�For an open circuit, or for load up to �$À.�# miliamperes�$4Use �$À#ohms �$À# watt resistor�$44Will the load (device) you use have larger than �$À#watts consumption?�$4(YES/NO)�$4;€
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6What is the voltage rating of REGULATORS�$4                  used with the power supply�$4;€"'À.��À.��À7
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6ÏPresuming that you use full wave, will the rectifying bridge�$4consist of four (4) or two (2) diodes (as in centertap sec)�$4;€"'À.�À.�
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À.�€ÀÀWhat is the load to be used in amperes? (if unknown type 0)�$4;€"'À.�7Z6?€À.�À.�€ÀÀ.��4Line = �$À# volts AC (max).Transformer primary (tap) = �$À	# volts AC�$4Secondary = �$À
# volts RMS. Peak sec.voltage = �$À#4For desired �$À# volts DC use rectifying bridge of �$À#4diodes rated at �$À# volts (minimum) and �$.�À#amps (min.)�$4Filter capacitor should be rated �$À# microfarads (minimum)�$4and �$À#volts DC (min).Permissible ripple = �$À# volts�$44NOTE:Use ohm-law to calculate bleeder-resistor.�$4More calculation for another secondary (YES/NO)�$4;€1'ÀYES�7u6	âMore calculation for another transformer (or tap)�$4;€1'ÀYES�7Á6	«6Ä6AYour secondary winding has overly high rating for this�$4power requirement�$446	âYour secondary winding has low voltage rating for this�$4power requirement�$446	âPower supply DC voltage must be more than 2.5 volts higher�$4     than voltage of REGULATOR.�$446
4Your supply voltage is overly high and will cause the regulator�$4to overheat. Reduce your voltage to �$À.��# volts�$4One way to do this is to insert series of diodes with rating�$4which will be printed below, each such diode reducing the�$4supply DC voltage by .7 volts (two diodes reduce 1.4 v)�$4Then add this voltage to regulators when answering Q.�$446
4How many TAB-type regulators will be used�$4;€"'         K-type regulators�$4;€"'Any other load (in ampers)�$4;€"'€ÀÀ.��À�6Z         *** LOW PASS FILTER ***�$4This program is based on OPERATIONAL AMPLIFIERS DESIGNS�$4& APPLICATIONS by Graeme & Tobey, McGraw, 1971.�$44Cut off frequency (in Hertz)�$4;€"'Desired pass-band gain (H)�$4;€"'Peaking factor: 0(zero) for standard 2-pole Butterworth�$4(alpha)         value for non-standard filter�$4;€"'À.�7.€.�.� ÀÀ.�!7=6dValue of C2 in mF (microFarads)�$4Note: 0.02 mF = 0.000 000 02 F     �$4;€"'€À.�"À�ÀÀ.�#4          .---------.                C1 = �$.�$.��À�ÀÀ.�%#4          X         :                C2 = �$À#4          X R2      = C2             R1 = �$ÀÀ#4          X         :                R2 = �$À#4    R1    :    R3   : - o            R3 = �$ÀÀ.���#4--XXXXXX--:--XXXXXX-:---o  o�$4          :             o    o�$4 E-in     :             o      o---------------�$4          = C1        + o    o�$4          :          ---o  o�$4          :          :  o           E-out�$4          :          :�$4----------:----------:--------------------------�$4Another gain/alpha ratio? (YES/NO)�$4;€1'ÀYES�7!6…Another filter configuration (YES/NO)�$4;€1'ÀYES�7a6_6d6ABecause operational amplifiers are non-ideal, pass-�$4band gain should be chosen to be less than 10 when peaking�$4factor Alpha = 0-1�$4Gain of 100 with peaking factor=1 is acceptable for �$4for peaking gain 80 dB in 2-pole Batterworth config-�$4uration.�$446…4          *** SERIES RESONANT FREQUENCY CIRCUITS ***�$44Inductance in MH (Milli-Henrys)�$4;€"'Capacitance in NF (Nano-Farads)�$4;€"'4Series L/C resonant frequency is �$.�&.�'ÀÀ.�(# KHz (Kilo Hertz)�$4Note: this frequency is not affected by resistance in the circuit�$44More calculations? (YES/NO)�$4;€1'ÀYES�7À6¨6A4      *** PASSIVE BANDPASS FILTER DESIGN ***�$44   This program is based on ELECTRICAL ENGINEERING &�$4CIRCUITS DESIGN by Skilling, Willey, 1961.�$4   It will calculate ideal component values for the�$4T-section and PI-Section filters, given F1, F2,and R�$44What is F1, low cut-off frequency (in Hertz)�$4;€"'What is F2, high cut-off frequency (in Hertz)�$4;€"'ÀÀ7C6dWhat is R, image impedance in mid-frequency (in ohms)�$4;€"'À.�7Ž6¯À.�7š6¯À.�7¦6¯€ÀÀ€.�)ÀÀ€À�If you want T-section type 'T'�$4;€1'ÀT�7ó6ð42Ca=�$ÀÀÀ.�*#5  Cb=�$.��ÀÀ#5  R=�$À#4La/2=�$ÀÀ.�+#5  Lb=�$ÀÀÀ#44    2Ca     La/2                La/2     2Ca�$4o----!!----mmmmmmm---:-----:---mmmmmmm---!!-.....�$4                     :     :                    :�$4                     :     m                    X�$4                  Cb =     m  Lb             R  X�$4                     :     m                    X�$4                     :     :                    :�$4o--------------------:-----:----------------....:�$44If you want PI-section type 'P'�$4;€1'ÀP�7&6Ý4La=�$ÀÀ#5  2Lb=�$.�,ÀÀÀ#5  R=�$À#4Ca=�$ÀÀÀ#5  Cb/2=�$.��ÀÀ.�-#44                 La       Ca�$4o-------:----:-mmmmmmm----!!-----:----:..........:�$4        :    :                   :    :          :�$4        m    :                   :    m          X�$4    2Lb m    = Cb/2        Cb/2  =    m 2Lb    R X�$4        m    :                   :    m          X�$4        :    :                   :    :          :�$4o-------:----:-------------------:----:..........:�$44Another passive filter calculation (YES/NO)�$4;€
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